Observe the following reaction:
`A(g) + 3B(g) rarr 2C(g)`
The rate of this reaction `{(-d[A])/(d t)}` is `3 xx 10^(-3) "mol litre"^(-1) "min"^(-1)`. What is the value of `(-d[B])/(d t)` in mol `"litre"^(-1) "min"^(-1)` ?

Options

A. `3 xx 10^(-3)`
B. `9 xx 10^(-3)`
C. `10^(-3)`
D. `1.5 xx 10^(-3)`

Answer

B

Explanation

`(-d[A])/(d t) = -(1)/(3)(d[B])/(d t)`
`:. (-d[B])/(d t) = 3 {(-d[A])/(d t)} = 3 xx 3 xx 10^(-3)`.