A gaseous hypothetical chemical equation `2A hArr 4B+C` is carries out in a closed vessel. The concentration of `B` is found to increase by `5 xx 10^(-3) mol L^(-1)` in `10` second. The rate of appearance of `B` is

Options

A. `5 xx 10^(-4) mol L^(-1) sec^(-1)`
B. `5 xx 10^(-5) mol L^(-1) sec^(-1)`
C. `6 xx 10-5 mol L^(-1) sec^(-1)`
D. `4 xx 10-4 mol L^(-1) sec^(-1)`

Answer

A

Explanation

Increase in concentration of `B = 5 xx 10^(-3) "mol L"^(-1)` Time `= 10 sec`
Rate of appearance of `B = ("Increase of conc. B")/("Time taken")`
`= (5 xx 10^(-3) mol 1^(-1))/(10sec) = 5 xx 10^(-4) mol 1^(-1) sec^(-1)`