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For the reaction A + B rarr C + D, doubl...

For the reaction `A + B rarr C + D`, doubling the concentration of both the reactants increases the reaction rate by `8` times and doubling the initial concentration of only `B` ismply doubles the reaction rate. What is the rate law for the reaction ?

A

`gamma = k[A][B]^(2)`

B

`gamma = k[A]^(2)[B]`

C

`gamma = k[A][B]`

D

`gamma = k[A]^(2)[B]^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`2A +B rarr` products
According to questio: Rate of reaction of `'A' prop [B]` as increas in rate is double when `[B]` is doubled.
Rate of reaction `prop [A] [B]` as increase in rate is `8` times when concentration of both reactant is doubled. It means that order of reaction is `3` and overall rate reaction should be `r = K[A]^(2)[B]`
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