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For the reaction H(2) + Br(2) rarr 2 HBr...

For the reaction `H_(2) + Br_(2) rarr 2 HBr` overall order is found to be `3//2`. The rate of reaction can be espressed as:

A

`[H_(2)][Br_(2)]^(1/2)`

B

`[H_(2)]^(1//2)[Br^(2)]`

C

`[H_(2)]^(3//2)[Br^(2)]^(0)`

D

All of these

Text Solution

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The correct Answer is:
D
By definition of roder.
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