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The energies of activation for forward ...

The energies of activation for forward and reverse reaction for `A_(2)+B_(2) hArr 2AB` are `180 kJ "mol"^(-1)` and `200 kJ "mol"^(-1)` respectively. The presence of catalyst lowers the activation energy of both (forward and reverse) reactions by `100 kJ "mol"^(-1)`. The enthalpy change of the reaction `(A_(2) + B_(2) rarr 2 AB)` in the presence of catalyst will be (in `kJ "mol"^(-1)`):

A

`300`

B

`120`

C

`280`

D

`-20`

Text Solution

Verified by Experts

The correct Answer is:
D

So, `Delta H_("reaction") = E_(f) - E_(b)`
`= 80-100=-20 kJ mol^(-1)`
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