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ArarrB, DeltaH= -10 KJ mol^(-1), E(a(f))...

`ArarrB, DeltaH= -10 KJ mol^(-1), E_(a(f))=50 KJ mol^(-1)`, then `E_(a)` of `BrarrA` will be

A

`40 kJ "mol"^(-1)`

B

`50 kJ "mol"^(-1)`

C

`-50 kJ "mol"^(-1)`

D

`60 kJ "mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`A rarr B, Delta H_(f) = -10kJ mol^(-1)` (Exothermic)
`:. B rarr A, Delta H_(b) + 10 kJ mol^(-1)` (endthermic)
`:. (E_(a))_(b) = Delta H_(b) + (E_(a))_(f)`
`= 10 + 50`
`= 60 kJ mol^(-1)`
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