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For a reaction, the rate constant is exp...

For a reaction, the rate constant is expressed as `k = Ae^(-40000//T)`. The energy of the activation is

A

`40000` cal

B

`88000` cal

C

`80000` cal

D

`8000` cal

Text Solution

Verified by Experts

The correct Answer is:
C
`(-E_(a))/(RT) = - 40000`
`E_(a) = 40000 xx 2 = 8 xx 10^(4) cal`
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