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For the reaction A + B products, it is o...

For the reaction `A + B` products, it is observed that:
(1) on doubling the initial concentration of `A` only, the rate of reaction is also doubled and
(2) on doubling te initial concentration of both `A` and `B`, there is a charge by a factor of `8` in the rate of the reaction.
The rate of this reaction is given by

A

rate `= k[A][B]`

B

rate `= k[A]^(2)[B]`

C

rate `= k[A][B]^(2)`

D

rate `= k[A]^(2)[B]^(2)`

Text Solution

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The correct Answer is:
To determine the rate law for the reaction \( A + B \rightarrow \text{products} \), we will analyze the given observations step by step. ### Step 1: Write the general rate law expression The rate of the reaction can be expressed as: \[ R = k [A]^n [B]^m \] where \( R \) is the rate of the reaction, \( k \) is the rate constant, \( n \) is the order of the reaction with respect to \( A \), and \( m \) is the order of the reaction with respect to \( B \). ### Step 2: Analyze the first observation The first observation states that when the concentration of \( A \) is doubled, the rate of reaction is also doubled. Mathematically, this can be expressed as: \[ 2R = k (2[A])^n [B]^m \] Dividing both sides by the original rate equation \( R = k [A]^n [B]^m \): \[ \frac{2R}{R} = \frac{k (2[A])^n [B]^m}{k [A]^n [B]^m} \] This simplifies to: \[ 2 = \frac{(2[A])^n}{[A]^n} = 2^n \] From this, we can deduce: \[ 2 = 2^n \implies n = 1 \] ### Step 3: Analyze the second observation The second observation states that when the concentrations of both \( A \) and \( B \) are doubled, the rate increases by a factor of 8: \[ 8R = k (2[A])^n (2[B])^m \] Using \( n = 1 \) from the previous step, we can rewrite this as: \[ 8R = k (2[A])^1 (2[B])^m = k (2[A][B]^m) \cdot 2^m \] Dividing both sides by the original rate equation: \[ \frac{8R}{R} = \frac{k (2[A])(2[B])^m}{k [A]^1 [B]^m} \] This simplifies to: \[ 8 = 2 \cdot 2^m \] Thus, we have: \[ 8 = 2^{1+m} \] This implies: \[ 8 = 2^3 \implies 1 + m = 3 \implies m = 2 \] ### Step 4: Write the final rate law Now that we have determined the values of \( n \) and \( m \): - \( n = 1 \) - \( m = 2 \) The rate law for the reaction is: \[ R = k [A]^1 [B]^2 \] or simply: \[ R = k [A] [B]^2 \] ### Summary of the Solution The rate of the reaction is given by: \[ R = k [A] [B]^2 \]

To determine the rate law for the reaction \( A + B \rightarrow \text{products} \), we will analyze the given observations step by step. ### Step 1: Write the general rate law expression The rate of the reaction can be expressed as: \[ R = k [A]^n [B]^m \] where \( R \) is the rate of the reaction, \( k \) is the rate constant, \( n \) is the order of the reaction with respect to \( A \), and \( m \) is the order of the reaction with respect to \( B \). ...
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