The half-life period of a radioactive element is `140` days. After `560` days, one gram of the element will reduce to

Options

A. `(1//2) g`
B. `(1//4) g`
C. `(1//8) g`
D. `(1//6) g`

Answer

D

Explanation

Fraction remaining `= ((1)/(2))^(n)`
`= ((1)/(2))^(560//140) = ((1)/(2))^(4) = (1)/(16)`