What will be the fraction of `._(m)^(n)X (t_(1//2) = 25 "min")` laft after `100` minutes?

Options

A. `1//2`
B. `1//4`
C. `1//3`
D. `1//16`

Answer

D

Explanation

fraction remaining `= ((1)/(2))^(n)`
`n =` no. of `t_(1//2)`
`=((1)/(2))^(100//25) = ((1)/(2))^(4) = (1)/(16)`