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The half-life of 2 sample are 0.1 and 0....

The half-life of `2` sample are `0.1` and `0.4` seconds. Their respctive concentration are `200` and `50` respectively. What is the order of the reaction

A

`0`

B

`2`

C

`1`

D

`4`

Text Solution

Verified by Experts

The correct Answer is:
B

`t_(1//2) = a^(1-n) rArr 0.1/0.4 =((200)^(1-n))/((50)^(1-n))`
`rArr (1)/(4) = [(4)/(1)]^(1-n) = [(1)/(4)]^(n-1)`
`rArr (1)/(4^(1)) = (1)/(4^(n-1))`
`:. n - 1 = 1, n = 2`
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