The rate constant, the activation energy and the Arrhenius parameter of a chemical reaction at `25^(@)C` are `3.0 xx 10^(-4) s^(-1), 104 "kJ mol"^(-1)` and `6.0 xx 10^(14)s^(-1)` respectively. The value of the rate constant as `T rarr oo` is

Options

A. `2.0 xx 10^(18)s^(-1)`
B. `6.0 xx 10^(14) s^(-1)`
C. Infinity
D. `3.6 xx 10^(30)s^(-1)`

Answer

B

Explanation

The Arrhenius equation is
`K = Ae^(-E_(a)//RT)`
As `T rarr oo` the value `(Ea)/(RT) rarr 0`
& `e^(-E_(a)//RT) rarr e^(-0) rArr 1`
Hence `k rarr A`
Hence `k = 6.0 xx 10^(14)s^(-1)`