Graph between `log x//m` and `log p` is a straight line inclined at an angle of `45^@` . When pressure is `0.5 atm` and `1n k = 0.693`, the amount of solute adsorbed per gram of adsorbent will be:

Options

A. 1
B. 1.5
C. 0.25
D. 2.5

Answer

A

Explanation

Log`x/M = log k + 1/n log P`
`1/n = tan 45^2` 1n `k = 0.69`
`n=1 k=2`
`x/m = 2xx(0.5)^(1)`
`x = 1`.