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Malachite on calcination gives rarr ‘A’ ...

Malachite on calcination gives `rarr ‘A’ +CO_(2) +H_(2)O`. Compound `‘A’` on reduction with carbon gives `rarr CO+ ‘B’`. Here ‘A’ and ‘B’are:

A

`Fe_(2),O_(3),Fe`

B

`CuO,Cu`

C

`CuCO_(3),CuO`

D

`MgO,Mg`

Text Solution

Verified by Experts

The correct Answer is:
B
`Cu(OH)_(2).CuCO_(3)rarr CUOunderset((a))+CO_(2) +H_(2)O`
`CUOunderset((b))+CrarrCO+Cu`
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A2Z-GENERAL PRINCIPLES AND PROCESS OF ISOLATION OF METALS-Metallurgy Of Cu, Fe, Ag, Al, Zn, And Au
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