The formation of `O_(2)^(+)[PtF_(6)]^(-)` is the basis for the formation of xenon fluorides. This is because:

Options

A. `O_(2)`and `Xe` have comparable sizes.
B. Both `O_(2)` and `Xe` are gases.
C. `O_(2)` and `Xe` have comparable ionisation energies.
D. `O_(2)` and `Xe` have comparable electronegativities.

Answer

C

Explanation

In march `1962`, neil bartlett, then at the university of british columbia, observed the reaction of a noble gas. First, the prepared a red compound which is formulated as `O_(2)^(+)[PtF_(6)]^(-)` and it is already know that the first ionistion enthalpy of molecular oxygen `(1175 kJ mol-1)` is almost similar with that xenon `(1170 kJ mol-1)` then he made efforts to prepare same type of compound by mixing `PtF_(6)` and Xenon `Xe^(+)[PtF_(6)]^(-)`. After this discovery, a number of xenon compounds minly with most electronegative elements like fluorine and oxygen, have been synthesised.