The highest oxidation state is exhibited by the transition metals with configuration:

Options

A. `(n - 1) d^(3) ns^(2)`
B. `(n - 1) d^(5) ns^(1)`
C. `(n - 1) d^(5) ns^(2)`
D. `(n - 1) d^(8) ns^(2)`

Answer

C

Explanation

it show maximum oxidation state equal to `+ 7` because the energy of `(n - 1)` d and ns orbitals are nearly same and thus seven electrons can participate in bonding.