Among the following series of transition metals ions, the one where all metal ions have `3d^(2)` electronic configuration is:

Options

A. `Ti^(+), V^(2+), Cr^(3+), Mn^(4+)`
B. `Ti^(+), V^(4+), Cr^(6+), Mn^(7+)`
C. `Ti^(2+), V^(3+), Cr^(2+), Mn^(3+)`
D. `Ti^(2+), V^(3+), Cr^(4+), Mn^(5+)`

Answer

D

Explanation

`._(22)Ti = 3 d^(2) 4s^(2), Ti^(2+) = 3 d^(2)`
`._(23)V = Cr = 3 d^(5) 4s^(1), V^(3+) = 3 d^(2)`
`._(24)Cr = 3 d^(5) 4s^(1) ,Cr^(4+) = 3 d^(2)`
`._(25)Mn = 3 d^(5) 4s^(2), Mn^(5+) = 3 d^(2)`