`KMnO_(4)` react with oxalic acid according to the equation, `2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) rarr 2Mn^(2+)+ 10 CO_(2)+8H_(2)O`, here `20 ml` of `0.1 M KMnO_(4)` is equivalemt to
A
`20 ml of0.5 M C_(2)H_(2)O_(4)`
B
`50 ml of 0.1 M C_(2)H_(2)O_(4)`
C
`20 ml of 0.5 M C_(2)H_(2)O_(4)`
D
`20 ml of 0.1 M C_(2)H_(2)O_(4)`
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The correct Answer is:
B
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