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KMnO(4) react with oxalic acid according...

`KMnO_(4)` react with oxalic acid according to the equation, `2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) rarr 2Mn^(2+)+ 10 CO_(2)+8H_(2)O`, here `20 ml` of `0.1 M KMnO_(4)` is equivalemt to

A

`20 ml of0.5 M C_(2)H_(2)O_(4)`

B

`50 ml of 0.1 M C_(2)H_(2)O_(4)`

C

`20 ml of 0.5 M C_(2)H_(2)O_(4)`

D

`20 ml of 0.1 M C_(2)H_(2)O_(4)`

Text Solution

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The correct Answer is:
B
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MnO_(4)^(-) + C_(2) O_(4)^(2-) + H^(+) = CO_(2) + Mn^(2+) + H_(2) O

KMnO_(4) reacts with oxalic acid according to the reaction : 2KMnO_(4) +5C_(2)O_(4)^(2-)+16 H^(+) to 2Mn^(2+) + 10 CO_(2) + 7H_(2)O Then, 20 mL of 0.1M KMnO_(4) is equivalent to :

Knowledge Check

  • KMnO_(4) reacts with oxalic acid according to the equation, 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+)to 2Mn^(2+)+10CO_(2)+8H_(2)O Here, 20 mL of 0.1 M KMnO_(4) is equivalent to :

    A
    120 mL of 0.25M `H_(2)C_(2)O_(4)`
    B
    `150 mL " of" 0.1 M H_(2)C_(2)O_(4)`
    C
    `50 mL " of" 0.1 M H_(2)C_(2)O_(4)`
    D
    `50 mL " of" 0.2 M H_(2)C_(2)O_(4)`

  • KMnO_(4) reacts with oxalic acid according to the equation 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to 2Mn^(2+)+10CO_(2)+8H_(2)O Here, 20 mL of 0.1 M KMnO_(4) is equivalent to:

    A
    120 mL of 0.25 M `H_(2)C_(2)O_(4)`
    B
    150 mL of 0.10M `H_(2)C_(2)O_(4)`
    C
    25 mL of 0.20 M `H_(2)C_(2)O_(4)`
    D
    50 mL of 0.20 M `H_(2)C_(2)O_(4)`

  • KMnO_(4) reacts with oxalic acid according to the equation 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to 2Mn^(2+)+10CO_(2)+8H_(2)O Here, 20mL of 1.0M KMnO_(4) is equivalent to:

    A
    `120mL` `of` `0.25M H_(2)C_(2)O_(4)`
    B
    `150mL` `of` `0.10M H_(2)C_(2)O_(4)`
    C
    `25mL` `of` `0.20M H_(2)C_(2)O_(4)`
    D
    `50mL` `of` `0.20M H_(2)C_(2)O_(4)`

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    KMnO_(4) reacts with oxalic acid according to the equation: 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to2Mn^(2+)+10CO_(2)+8H_(2)O 20mL of 0.1M KMnO_(4) will react with:

    KMnO_(4) reacts with ferrous ammonium sulphate according to the equation MnO_(4)^(-)+5Fe^(2+)+8H^(+) rarr Mn^(2+)+5Fe^(3+)+4H_(2)O , here 10 ml of 0.1 M KMnO_(4) is equivalent to

    In the redox reaction, 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to 2Mn^(2+)+10CO_(2)+8H_(2)O 20mL of 0.1 M KMnO_(4) reacts quantitatively with :

    The oxidising agent in the reaction 2MnO_(4)^(-) +16H^(+) +5C_(2)O_(4)^(-2) rarr 2Mn^(+2) +8H_(2)O +10CO_(2)

    In the reaction C_(2)O_(4)^(2-)+MnO_(4)^(-)+H^(+) rarr Mn^(2+)+CO_(2)+H_(2)O the reductant is

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