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If excess of NH(4)OH is added to CuSO(4)...

If excess of `NH_(4)OH` is added to `CuSO_(4)` solution, it forms blue coloured complex which is

A

`Cu (NH_(3))_(4) SO_(4)`

B

`Cu(NH_(3))_(2)SO_(4)`

C

`Cu (NH_(4))_(4) SO_(4)`

D

`Cu (NH_(4))_(2)SO_(4)`

Text Solution

Verified by Experts

The correct Answer is:
A
`CuSO_(4) + 4NH_(4)OH rarr underset(Blue)([Cu(NH_(3))_(4)]SO) + 4H_(2)O`
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