Excess of `KI` reacts with `CuSO_(4)` solution and `Na_(2)SO_(3)` solution is added to it. Which of the following statements in incorrect for the reaction?

Options

A. `Na_(2) S_(2) O_(3)` is oxidised
B. `C u l_(2)` formed
C. `Cu_(2) I_(2)` is formed
D. Evolved `I_(2)` is reduced

Answer

B

Explanation

`2 overset(-1)KI + 2CuSO_(4) rarr overset(0)I_(2) + Cu_(2) I_(2) + 2K_(2) SO_(4)`
`overset(0)I_(2) + 2Na_(2) overset(+2)S_(2) O_(3) rarr overset(+2.5)Na_(2) S_(4) O_(6) + 2overset(-1)Nal`