`KMnO_(4)` reacts with ferrous ammonium sulphate according to the equation `MnO_(4)^(-)+5Fe^(2+)+8H^(+) rarr Mn^(2+)+5Fe^(3+)+4H_(2)O`, here `10 ml` of `0.1 M KMnO_(4)` is equivalent to

Options

A. `20 ml` of `0.1 m FeSO_(4)`
B. `30 ml` of `0.1 M FeSO_(4)`
C. `40 ml` of `0.1 M FeSO_(4)`
D. `50 ml` of `0.1 M FeSO_(4)`

Answer

D

Explanation

In this reaction
`underset(1)MnO_(4)^(-) + 5 underset(5)Fe_(5)^(2+) + 8 H^(+) + 4H_(2)O`
5 time quantity of `Fe^(+2)` consumed.
So 5 time of `FeSO_(4)` will be equivalent to `50 ml`