Which of the following has the highest molar conductivity in solution?

Options

A. (a) `[Pt(NH_3)_6]Cl_4`
B. (b) `[Pt(NH_3)_5Cl]Cl_3`
C. (c) `[Pt(NH_3)_4Cl_2]Cl_2`
D. (d) `[Pt(NH_3)_3Cl_3]Cl`

Explanation

To determine which compound has the highest molar conductivity in solution, we need to analyze the dissociation of each compound into its constituent ions. Molar conductivity is directly related to the number of ions produced when a compound is dissolved in solution. The more ions produced, the higher the molar conductivity.

### Step-by-Step Solution:

1. **Identify the Compounds**: First, we need to identify the coordination compounds given in the question. For this example, let's assume the compounds are:
- \( \text{[Pt(NH}_3\text{)}_6\text{Cl}_4] \)
- \( \text{[Pt(NH}_3\text{)}_5\text{Cl}]_2 \)
- \( \text{[Pt(NH}_3\text{)}_4\text{Cl}_2] \)
- \( \text{[Pt(NH}_3\text{)}_3\text{Cl}_3] \)

2. **Dissociation of Each Compound**:
- For \( \text{[Pt(NH}_3\text{)}_6\text{Cl}_4] \):
- Dissociates into \( \text{[Pt(NH}_3\text{)}_6]^{4+} + 4 \text{Cl}^- \)
- Total ions = 1 + 4 = 5 ions
- For \( \text{[Pt(NH}_3\text{)}_5\text{Cl}]_2 \):
- Dissociates into \( \text{[Pt(NH}_3\text{)}_5]^{2+} + 2 \text{Cl}^- \)
- Total ions = 1 + 2 = 3 ions
- For \( \text{[Pt(NH}_3\text{)}_4\text{Cl}_2] \):
- Dissociates into \( \text{[Pt(NH}_3\text{)}_4]^{2+} + 2 \text{Cl}^- \)
- Total ions = 1 + 2 = 3 ions
- For \( \text{[Pt(NH}_3\text{)}_3\text{Cl}_3] \):
- Dissociates into \( \text{[Pt(NH}_3\text{)}_3]^{3+} + 3 \text{Cl}^- \)
- Total ions = 1 + 3 = 4 ions

3. **Count the Total Ions**: Now we summarize the total ions produced from each compound:
- \( \text{[Pt(NH}_3\text{)}_6\text{Cl}_4] \) → 5 ions
- \( \text{[Pt(NH}_3\text{)}_5\text{Cl}]_2 \) → 3 ions
- \( \text{[Pt(NH}_3\text{)}_4\text{Cl}_2] \) → 3 ions
- \( \text{[Pt(NH}_3\text{)}_3\text{Cl}_3] \) → 4 ions

4. **Determine the Highest Molar Conductivity**: The compound that produces the highest number of ions will have the highest molar conductivity. From our analysis:
- \( \text{[Pt(NH}_3\text{)}_6\text{Cl}_4] \) produces 5 ions, which is the highest.

### Conclusion:
Thus, the compound with the highest molar conductivity in solution is \( \text{[Pt(NH}_3\text{)}_6\text{Cl}_4] \).