Coordination number of `Ni` in `[Ni(C_2O_4)_3]^(4-)` is:

Options

A. (a) `3`
B. (b) `4`
C. (c) `5`
D. (d) `6`

Answer

D

Explanation

`C_2O_4^(2-)` is a bidentate group. As the complex contains three bidentate groups, the central metal ion has a coordination number of 6.