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Among the following which are ambidentat...

Among the following which are ambidentate ligands?
(i) `NO_2^(-)`
(ii) `NO_3^(-)`
(iii) `C_2O_4^(2-)`
(iv) `SCN^(-)`

A

(a) (i) and (iv)

B

(b) (i) and (ii)

C

(c) (ii) and (iii)

D

(d) (iii) and (iv)

Text Solution

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The correct Answer is:
To determine which of the given ligands are ambidentate, we need to analyze each ligand to see if it can coordinate through two different atoms. ### Step-by-Step Solution: 1. **Identify the Ligands**: The ligands provided are: - (i) `NO_2^(-)` - (ii) `NO_3^(-)` - (iii) `C_2O_4^(2-)` - (iv) `SCN^(-)` 2. **Analyze `NO_2^(-)`**: - The nitrite ion (`NO_2^(-)`) has a nitrogen atom and two oxygen atoms. - The nitrogen can donate a lone pair, and one of the oxygen atoms carries a negative charge and can also donate a lone pair. - Therefore, `NO_2^(-)` can coordinate through both nitrogen and oxygen, making it an ambidentate ligand. 3. **Analyze `NO_3^(-)`**: - The nitrate ion (`NO_3^(-)`) has a nitrogen atom bonded to three oxygen atoms. - However, the nitrogen does not have a lone pair available for donation, and only one of the oxygen atoms can donate a pair of electrons. - Thus, `NO_3^(-)` cannot coordinate through two different atoms and is not an ambidentate ligand. 4. **Analyze `C_2O_4^(2-)`**: - The oxalate ion (`C_2O_4^(2-)`) has two carbon atoms and four oxygen atoms. - Although it has multiple oxygen atoms, they are all similar in terms of their ability to donate electrons (they are all oxygen). - Therefore, `C_2O_4^(2-)` does not qualify as an ambidentate ligand since it does not coordinate through two different types of atoms. 5. **Analyze `SCN^(-)`**: - The thiocyanate ion (`SCN^(-)`) consists of a sulfur atom and a nitrogen atom. - The sulfur atom has a negative charge and can donate a lone pair, while the nitrogen atom can also donate a lone pair. - Since it can coordinate through both sulfur and nitrogen, `SCN^(-)` is an ambidentate ligand. ### Conclusion: The ambidentate ligands among the given options are: - (i) `NO_2^(-)` - (iv) `SCN^(-)` ### Summary of Results: - Ambidentate Ligands: `NO_2^(-)` and `SCN^(-)` - Non-ambidentate Ligands: `NO_3^(-)` and `C_2O_4^(2-)`

To determine which of the given ligands are ambidentate, we need to analyze each ligand to see if it can coordinate through two different atoms. ### Step-by-Step Solution: 1. **Identify the Ligands**: The ligands provided are: - (i) `NO_2^(-)` - (ii) `NO_3^(-)` ...
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A2Z-COORDINATION COMPOUNDS-Section D - Chapter End Test
  1. Among the following which are ambidentate ligands? (i) NO2^(-) (i...

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  2. Co-ordination number of Fe in the complexes [Fe(CN)6]^(4-), [Fe(CN)6]^...

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  3. (Me)(2) SiCl(2) on hydrolysis will produce.

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  4. Types of isomerism shown by [Cr(NH3)5NO2]Cl2 is

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  5. Which of the following will no give a precipate with AgNO3?

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  6. In the process of extraction of gold, Roasted gold ore +CN^(-)+H2Oov...

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  7. A reagent used for identifying nickel ion is:

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  8. Which of the following complex is an outer orbital complex?

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  9. Which of the following has the largest number of isomers? .

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  10. Which kind of isomerism is exhibited by octahedral [Co(NH(3))(4)Br(2)]...

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  11. Which one of the following is expected to exhibit optical isomerism (e...

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  12. The pair of the compounds in which both the metals are in the highest ...

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  13. IUPAC name of [Co(NH3)5NO2]Cl2

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  14. Which of the following is considered to be an anticancer species ?

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  15. An aqueous solution of COCL2 on addition of excess of concentrated HCl...

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  16. The correct order for the wavelength of absorption in the visible regi...

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  17. In which of the following pairs both the complex show optical isomeris...

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  18. Which of the following compounds shows optical isomerism?

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  19. CN^(-) is a strong field ligand. This is due to the fact that

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  20. Considering H2O as a weak field ligand, the number of unpaired electro...

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  21. Given the molecular formula of the hexacoordinated complexes (A) [CoCl...

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