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The number of ions formed when cuprammon...

The number of ions formed when cuprammonium sulphate is dissolved in water is

A

(a) `1`

B

(b) `2`

C

(c) `4`

D

(d) Zero

Text Solution

Verified by Experts

The correct Answer is:
B
Cuprammonium salt-`[Cu(NH_3)_4]SO_4`
`[Cu(NH_(3))_(4)]SO_4 hArr [Cu(NH_3)_4]^(2+) + SO_(4)^(2-)`
So, it will give two ions in water.
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