Considering `H_2O` as a weak field ligand, the number of unpaired electrons in `[Mn(H_2O)_6]^(2+)` will be (At. no. of `Mn=25`)

Options

A. (a) two
B. (b) four
C. (c) three
D. (d) five

Answer

D

Explanation

`Mn^(25)rarr3d^5+4s^2`
` Mn^(2+) to 3d^(6) (##A2Z_CHM_XII_C09_E01_279_S01.png" width="80%">
In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons `=5`.