Cobalt (III) chloride forms several octahedral complexes with amonia. Which of the following will not give test for chloride ions with silver nitrate at `25^@C`?

Options

A. (a) `CoCl_3*5NH_3`
B. (b) `CoCl_3*6NH_3`
C. (c) `CoCl_3*3NH_3`
D. (d) `CoCl_3*4NH_3`

Answer

C

Explanation

For octahedral complexes, coordination number is 6. Hence, `CoCl_3 diamond 3NH_3`, i.e., `[Co(NH_3)_3diamondCl_3]` will not ionize and will not give test for `Cl^(-)` ions with silver nitrate.