Both `[Ni(CO)_4]` and ` [Ni (CN)_4]^(2-) ` are diamagnetic The hybridisations of nickel in these complexes , respectively are :

Options

A. (a) `d^2sp^2`
B. (b) `d^2sp^3`
C. (c) `dsp^2`
D. (d) `sp^3`

Answer

C

Explanation

`[Ni(CN)_4]^(2-)`
Oxidation state of `Ni` is `+2`
`x-4=2`
`x=+2`
`Ni^(2+)rarr[Ar]^(18)3d^84s^(0)`

due to presence of strong field ligand all unpaired electrons are paired up.

Hybridisation is `dsp^2`.