In the following reaction
`C_(6)H_(5)CH_(2)Br underset(2.H_(3)O)overset(1." Mg.Ether")rarrX`, the pr oduct 'X' is` .

Options

A. `C_(6)H_(5)CH_(2)OCH_(2)C_(6)H_(5)`
B. `C_(6)H_(5)CH_(2)OH`
C. `C_(6)H_(5)CH_(3)`
D. `C_(6)H_(5)CH_(2)CH_(2)C_(6)H_(5)`

Explanation

To solve the given reaction, we will follow these steps:

### Step 1: Identify the Reactants
The reactant given is benzyl bromide, which has the formula \( C_6H_5CH_2Br \).

### Step 2: First Reaction with Magnesium in Ether
In the first step, benzyl bromide reacts with magnesium in an ether solvent. This reaction forms a Grignard reagent. The Grignard reagent formed from benzyl bromide is:

\[ C_6H_5CH_2Br + Mg \xrightarrow{\text{Ether}} C_6H_5CH_2MgBr \]

### Step 3: Hydrolysis of the Grignard Reagent
The next step involves the hydrolysis of the Grignard reagent. When \( C_6H_5CH_2MgBr \) is treated with water (or \( H_3O^+ \)), the Grignard reagent reacts with water to produce an alcohol and a byproduct. The reaction can be represented as:

\[ C_6H_5CH_2MgBr + H_3O^+ \rightarrow C_6H_5CH_3 + Mg(OH)Br \]

### Step 4: Identify the Product
The product formed from this reaction is toluene, which has the formula \( C_6H_5CH_3 \). The byproduct is magnesium hydroxide bromide \( Mg(OH)Br \).

### Final Answer
Thus, the product \( X \) is **toluene** (\( C_6H_5CH_3 \)).

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