Treatment of ammonia with excess of ethyl chloride will yield

Options

A. Diethyl amine
B. ethane
C. Tetraethyl ammonium chloride
D. methyl amine

Answer

C

Explanation

`C_(2)H_(5)Cioverset(NH_(3))rarr C_(2)H_(5)-NH_(2)`
`overset(C_(2)H_(5)CI)rarr(C_(2)H_(5))_(2)-NH`
`overset(C_(2)H_(5)CI)rarr(C_(2)H_(5))_(3)N`
`overset(C_(2)H_(5)CI)rarr [underset("Tetraethylammonium chloride")[C_(2)H_(5)-underset(C_(2)H_(5))underset(|)overset(C_(2)H_(5))overset(|)N-C_(2)H_(5)]CIbar]`
If `NH_(3)` is in excess then `1^(@)` amine will be the main product if `C_(2)H_(5)CI` is in excess then mixture of `1^(@)` ,`2^(@)` ,`3^(@)` and quaternary amine is obtained .