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Decreasing order of reactivity in Willia...

Decreasing order of reactivity in Williamson synthesis orf the following .
`Me_(3)C CH_(2)Br`
`CH_(3)CH_(2)CH_(2)Br`
`CH_(2)=CHCH_(2)CI`
`CH_(3)CH_(2)CH_(2)CI` .

A

IIIgtIIgtIVgtI

B

IgtIIgtIVgtIII

C

IIgtIIIgtIVgtI

D

IgtIIIgtIIgtIV

Text Solution

Verified by Experts

The correct Answer is:
A
Williamson' s synthesis in `S_(N)2` Less is steric hindrance around carbon bearing halogen more is reactivity `sp^(2)` hybridized carbon of allyl is planar .
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Decreasing order of reactivity in Williamson's ether synthesis of the following . I. Me_3"CC"H_2Br II. CH_3CH_2CH_2Br III. CH_2=CHCH_2Cl IV. CH_3CH_2CH_2CH_2Cl

Arrange the following halides in decreasing order of reactivity for Williamson's synthesis : CH_(3)CH_(2)CH_(2)Br,CH_(3)CH_(2)CH_(2)Cl, H_(2)C=CH-CH_(2)Cl,CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(2)Br

Give the decreasing order of reactivity of the following alkyl halides in the Williamson's reaction. i. (CH_(3))_(3)C-CH_(2)Br ii. CICH_(2)CH=CH_(2) iii. (CICH_(2)CH_(2)CH_(3) iv. BrCH_(2)CH_(2)CH_(3)

The increasing order of reactivity of the following halides for the S_(N)1 reaction is I. CH_(3)CH(CI)CH_(2)CH_(3) II . CH_(3)CH_(2)CH_(2)Cl III. p. -H_(3)CO-C_(6)H_(4)-CH_(2)Cl

Predict the order of reactivity of the following compounds in dehydrohalogenation: (a) CH_(3)CH_(2)CH_(2)CH_(2)Cl, (CH_(3))_(2)CHCH_(2)Cl, (CH_(3))_(2)CH-CH_(2)Br, CH_(3)CH(Br)CH_(2)CH_(3), (CH_(3))_(3)C-Br (b) CH_(3)CH(Br)CH_(3), CH_(3)CH_(2)CH_(2)Br, (CH_(3))_(2)CHCH_(2)Br, (CH_(3))_(3)C CH_(2)Br

The correct order increasing reactivity of the following alkyl halides. CH_(3)CH_(2)CH(Br)CH_(3) (i) , CH_(3)CH_(2)CH_(2)CH_(2)Br(II), (CH_(3))_(2)C CICH_(2) CH_(3) (III) " and " CH_(3)CH_(2) CH_(2) CI (IV) towards S_(N^(2)) displacement is :

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