Treatment of ammonia with excess of ethyl chloride will yield

Options

A. Diethyl amine
B. Ethane
C. Tetraethyl ammonium chloride
D. Methyl mine

Answer

C

Explanation

`C_(2)H_(5)CIoverset(NH_(3))rarrC_(2)H_(5)-NH_(2)overset(C_(2)H_(5)CI)rarr(C_(2)H_(5))_(2)-NH`
`overset(C_(2)H_(5)CI)rarr(C_(2)H_(5))_(3)Noverset(C_(2)H_(5)CI)rarr[underset("Tetraethyl ammonium chloride")(C_(2)H_(5)-underset(C_(2)H_(5))underset(|)overset(C_(2)H_(5))overset(|)N-C_(2)H_(5)]]^(+)CIbar`
if `NH_(3)` is in excess then `1^(@)` amine will be the main product if `C_(2)H_(5)CI` is in excess then mixture of `1^(@)2^(@)3^(@)` and quaternary amine is obtained .