An alcohol contains `60%` carbon and `13.3%` hydrogen and givens positive idoform test. The alcohol is

Options

A. `2-`propanol
B. `1-`propanol
C. `2-`butanol
D. `1-`butanol

Answer

A

Explanation

`C:H:O = (60)/(12):(13.3)/(1):(26.7)/(16) = (5)/(1.67):(13.3)/(1.67):(1.67)/(1.67) = 3:8:1`
The formula of the compound is `CH_(3)H_(8)O`.
Since the alcohol gives positive iodoform test. It has `CH_(3)-underset(H)underset(|)overset(|)C-OH`, hence it is `2`-propanol.
`(underset(OH)underset(|)(CH_(3)CHCH_(3)))`