At low temperature phenol reacts wity `Br_(2)` in `CS_(2)` to form

Options

A. `m`-bromophenol
B. `p`-bromophenol
C. `o`-and `p`-bromophenol
D. `2,4,6-`tribromophenol

Answer

C

Explanation

In presence of non-polar solvent `(CS_(2))` the ionization phenol is suppressed. The ring is slightly activated and hence mono substitution occurs.
On the other hand with `Br_(2)` and water, phenol forms `2,4,6`-tribromo phenol.

In aqueous solution phenol ionizes to give phenoxide ion. Due to the presence of negative charge on oxygen the benzene ring is highly activiated and hence trisubtituted product is obtained.