When benzene sulphonic acid and p-nitrophenol are treated with `NaHCO_3`, the gases released respectively, are :

Options

A. `N_(2),CO_(2)`
B. `CO_(2),SO_(2)`
C. `N_(2),SO_(2)`
D. `CO_(2),CO_(2)`

Answer

D

Explanation

`underset((I))(PhSO_(3)H)+NaHCO_(3)erarrPhSO_(3)Na+H_(2)O+CO_(2)`
Since both (I) and (II) are stronger acids than `H_(2)CO_(3)`, they are capable of evolving `CO_(2)` with `NaHCO_(3)`.
`underset((II))(p-NO_(2))-C_(6)H_(4)-OH+NaHCO_(3)rarr p-NO_(2)-C_(6)H_(4)ONa +H_(2)O +CO_(2)`
`HCO_(3)^(-) +H^(+)rarr H_(2)O +CO_(2)uarr`