In the reaction, the produces formed are
`(CH_(3))_(2)CH_(2).CH_(2).O.CH_(2)CH_(3)+HI overset(Heated)rarr`

Options

A. `(CH_(3))_(2)CHCH_(2)I+CH_(3)CH_(2)OH`
B. `(CH_(3))_(2)CH.CH_(2)OH+C_(2)H_(6)`
C. `(CH_(3))_(2)CH.CH_(2)OH+C_(2)H_(5)I`
D. `(CH_(3))_(2)CH.CH_(2)I+CH_(3)CH_(2)OH`

Answer

A

Explanation

In the cleavage of mixed ethers with two different alky`1` groups, the alcohol and alky`1` iodide that form depend on the nature of alky`1` group. When primary or secondary alky`1` groups are present, it is the lower alky`1` group that froms alky`1` iodide therefore
`CH_(3)underset(CH_(3))underset(|)(CH)-CH_(2)-O-CH_(2)-CH_(3)+HI`
`overset(Delta)rarrCH_(3)-overset(CH_(3))overset(|)(CH)-CH_(2)OH+CH_(3)CH_(2)I`