Among the following ethers, which one will produce methyl alcohol on treatment with hot concentrated `HI`?

Options

A. `CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-O-CH_(3)`
B. `CH_(3)-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(C)-O-CH_(3)`
C. `CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-O-CH_(3)`
D. `CH_(3)-CH_(2)-CH_(2)-CH_(2)-O-CH_(3)`

Answer

B

Explanation

The ether, which give more stable carbocaiton, gives `CH_(3)OH` as one of product with concentrated `HI`. The order of stability of carbocations is `3^(@) gt 2^(@) gt 1^(@)`.
`CH_(3)-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(C)-O-CH_(3)overset(HI)underset(S_(N)I)rarr underset("more stable "3^(@)" carbocation")(CH_(3)-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(C^(+)))overset(HI)rarrCH_(3)-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(C^(+))-I`