A `0.1` molal solution of `NaCI` found to be isotomic with `1%` urea solution , calculate `alpha` and `i` for `NaCI`

Options

A. `i = 1.66 alpha= 0.66`
B. `i = 2.66 alpha= 0.66`
C. `i = 1.66 alpha= 2.66`
D. `i = 3.66 alpha= 2.66`

Answer

a

Explanation

`i_(1)(CM)_(1) = i_(2) (CM)_(2)`
`i_(1) (0.1) + (((W)/(V))% xx 10)/(M W) rArr i_(1) = (1 xx 10)/(60 xx 0.1)`
`rArr i = (10)/(6) = 1.66 alpha = (i - 1)/(n - 1)`
`alpha = (1.66 - 1)/(2-1)`