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CH(3)CH(2)underset(Br)underset(|)(CH)CH(...

`CH_(3)CH_(2)underset(Br)underset(|)(CH)CH_(2)CH=CH_(2) overset("alcoholic KOH")rarr A` (predominant) A is

A

`CH_(3)CH_(2)CH = CHCH = CH_(2)`

B

`CH_(3)CH=CHCH_(2)CH = CH_(2)`

C

`CH_(2)=CHCH_(2) = CH_(2)CH_(2)`

D

`CH_(3)CH_(2)CH_(2) CH_(2)C = CH`

Text Solution

Verified by Experts

The correct Answer is:
a
`CH_(3)CH_(2)underset(Br)underset(|)(CH)CH_(2)CH=CH_(2) rarr CH_(3)CH_(2)CHCH_(2)CH = CH_(2)overset(-H^(+))rarr CH_(3)CH_(2)CH = CHCH = CH_(2)`
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