During the electrolysis of the aqueous solution of copper sulphate using `Pt` electrode, the reaction taking place at anode electrode is

Options

A. `Cu^(2-) + 2e^(-) rarr Cu`
B. `Cu + rarr Cu^(2+) + 2e^(-)`
C. `2H_(2)O rarr 4H^(o+) + O_(2) + 4e^(-)`
D. `H_(2)O + e^(-) rarr overset(Theta)(OH ) + 1//2 H_(2)`

Answer

c

Explanation

At anode oxidation of `H_(2)O` occure since the oxidetion potential of `H_(2)O` is greater than the oxidation potential of `SO_(4)^(2)` ion.