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The edge of unit cell of FC C ionic ceys...

The edge of unit cell of `FC C` ionic ceystal is `620` pm. The radius of cation is`134`pm.What is the radius of anion?

A

168 pm

B

176 pm

C

184 pm

D

152 pm

Text Solution

Verified by Experts

The correct Answer is:
B
For ionic substance in `FC C`arrangement,
`2(r^(+)r^(-))="edge length"`
`r^(+)+r^(-)=310 "pm"`
`134+r^(-)=310 "pm"`
`r^(-)=176 "pm"`
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