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The molal elevation constant of water =0...

The molal elevation constant of water =`0.52 K m^(-1)`. The boiling point of `1.0 molal` aqueous `KCl` solution (assuming complete dissociation of `KCl`) should be

A

`98.96^(@)C`

B

`100.52^(@)C`

C

`101.04^(@)C`

D

`104.01^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
`i=2(KClrarrK'+Cl)`
`DeltaT_(b)=iK_(b)m=2xx052xx1=1.04`
`:.T_(b)=101.04^(@)C`
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