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In a first order reaction initial concen...

In a first order reaction initial concentration of a substance becoming the half is`100`sec,then calculation the time requird to reduce the concentration of reaction 0.0125 M from 0.05 M

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The correct Answer is:
C
For the first order reaction
`K=(0.693)/(t_(t//2))=(0.693)/(100)=6.93xx10^(-3)sec^(-1)`
`K=(2.303)/(t)"log"_(10)(a)/(a-x)`
`t=(2.303)/(6.93xx10^(-3)) "log"_(10)(0.05)/(0.125)=200sec`
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