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0.4 gm of an organic compound was treate...

0.4 gm of an organic compound was treated according to Kjeldahl's method. The ammonia evoled was absorbed in 50 ml or `0.5MH_3PO_3`. The residual acid required 30 ml of `0.5MCa(OH)_2` Find the percentage of `N_2` in the compound.

A

`54%`

B

`62%`

C

`56%`

D

`51%`

Text Solution

Verified by Experts

The correct Answer is:
C
Milliequivalents of acid=`50xx0.5xx2=50`
Milliequivalents of base=`60xx(1)/(2)xx1=30`
Excess of acid used to neutralize`NH_(3)`
`=50-30=20m`
`%N_(2)=(1.4xxm."Eq of acid used")/("Weight of compound")=(1.4xx20)/(0.5)=56%`
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