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The values of wedge(m)^(oo) forNH(4)Cl,N...

The values of `wedge_(m)^(oo)` for`NH_(4)Cl,NaOH,` and `NaCl` are, respectively, `149.74,248.1`,and `126.4 ohm^(-1)cm^(2)eq^(-1)`. The value of `wedge_(eq)^(oo)NH_(4)OH` is

A

` 371.44`

B

` 271.44`

C

` 71. 44`

D

It cannot be calculated from the data given

Text Solution

Verified by Experts

The correct Answer is:
B
`Lambda_(eq)^(infty) ` or ` Lambda_(CH_4OH)^(infty) = Lambda_(eq_(NH_4Cl))^(infty) + Lambda_(eq_(NaOH)^(infty) -Lambda(eq_(NaCl))^(infty)`
` = (149. 74 + 248.1 - 126.4) = 271. 44 "ohm"^(-1) cm^2 eq^(-1)`.
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