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When .(92)U^(238) decauys it emits an a-...

When `._(92)U^(238)` decauys it emits an a-particle. The new nuclide in turn emits a beta-particele to give another nuclide X. The mass number and atomic number of X are. Respectively .

A

` 234 ` and ` 91`

B

` 234 `and ` 96`

C

` 231` and ` 88`

D

` 234` and ` 88`

Text Solution

Verified by Experts

The correct Answer is:
A
`. _(92) U^(238) rarr _zX^A +_2 H_(e)^(4)+_(-1)e^0`
Equating mass number on both sides
` 238 = A+4 0`
` :. A= 238 - 4 = 234`
Equating atomic numer on both sides
` 92 = Z + 2 -1`
` :. Z= 92 -1 =91`.
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