Let `R` be a relation on `N` defined by `x+2y=8.` The domain of `R` is (a) {2, 4, 8} (b) {2, 4, 6, 8} (c) {2, 4, 6} (d) {1, 2, 3, 4}

1.Let R be a relation on N defined by x+2y=8 . The domain of R is

1.Let R be a relation on N defined by x+2y=8 . The domain of R is

Let R be a relation on N defined by R={(x,y):x+2y=8). Then domain of R is

Let R be a relationon N defined by x+2y=8. The domain of R is (a) {2,4,8} b. {2,4,6,8} c. {2,4,6} d. (1,2,3,4)

Let R be a relationon N defined by x+2y=8. The domain of R is {2,4,8} b.{2,4,6,8} c.{2,4,6} d.(1,2,3,4)

Let R be a relation on the set N given by R={(a ,\ b): a=b-2,\ b >6}dot Then, (2,\ 4) in R (b) (3,\ 8) in R (c) (6,\ 8) in R (d) (8,\ 7) in R

Let R be a relation on the set N given by R={(a ,\ b): a=b-2,\ b >6}dot Then, (a) (2,\ 4) in R (b) (3,\ 8) in R (c) (6,\ 8) in R (d) (8,\ 7) in R

Let A = {2, 4, 6, 8} and define R = {(2, 4), (4, 2), (4, 6), (6, 4)} then R is

Let X = {1, 2, 3, 4, 5, 6, 7, 8, 9} . Let R_1 be a relation in X given by R_1 = {(x, y) : x – y is divisible by 3} and R_2 be another relation on X given by R_2 = {(x, y): {x, y} sub {1, 4, 7} or {x, y} sub {2, 5, 8} or {(x, y} sub {3, 6, 9} . Show that R_1 = R_2 .

Let R be a relation on a set A = {1,2,3,4,5} defined as R = { (a,b) : | a ^(2) - b ^(2)| lt8}. Then the reation R is