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The bond energies in NO, NO^(+), NO^(-) ...

The bond energies in `NO, NO^(+), NO^(-)` follow the order

A

`NO^(+) gt NO gt NO^(-)`

B

`NO^(+) lt NO lt NO^(-)`

C

`NO^(+) lt NO gt NO^(-)`

D

`NOgt NO^(+) gt NO^(-)`

Text Solution

Verified by Experts

The correct Answer is:
A

Bond order NO `= (1)/(2) (10 - 5) = 2.5 `
Bond order `NO^(+) = (1)/(2) (10 - 4) = 3.0 `
Bond order `NO^(-) = (1)/(2) (10 - 6) = 2.0 `
Since bond energies directily related to bond order .Therefore cannot order of increasing bond energies is `NO^(+) gt NO gt NO^(-)`
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