The highest amount of s-character is observed in :

Options

A. `N - H` hond of `NH_(3)`
B. `N - H` bond of `NH_(4)^(+)`
C. `N-H` bond in `underset(("Hydrazine"))(H_(2)N NH_(2))`
D. `N-H` bond in `underset(("Diazene"))(HN=NH)`

Explanation

To determine which NH bond has the highest amount of s-character, we need to analyze the hybridization of the nitrogen atoms in the given compounds: NH3 (ammonia), NH4+ (ammonium ion), NH2 (hydrazine), and diazene (N2H2).

### Step-by-Step Solution:

1. **Analyze NH3 (Ammonia)**:
- Nitrogen has 5 valence electrons.
- In NH3, there are 3 hydrogen atoms (monovalent).
- There are no cations or anions.
- Calculation:
\[ \text{Valence Electron Count} = \frac{(5 + 3 - 0 + 0)}{2} = \frac{8}{2} = 4 \]
- The steric number is 4, which corresponds to sp³ hybridization.
- **S-character**:
\[ \text{S-character} = \frac{1}{4} \times 100 = 25\% \]

2. **Analyze NH4+ (Ammonium Ion)**:
- Nitrogen has 5 valence electrons.
- In NH4+, there are 4 hydrogen atoms.
- There is a +1 cationic charge.
- Calculation:
\[ \text{Valence Electron Count} = \frac{(5 + 4 - 1 + 0)}{2} = \frac{8}{2} = 4 \]
- The steric number is 4, which also corresponds to sp³ hybridization.
- **S-character**:
\[ \text{S-character} = \frac{1}{4} \times 100 = 25\% \]

3. **Analyze NH2 (Hydrazine)**:
- Nitrogen has 5 valence electrons.
- In NH2, there are 2 hydrogen atoms.
- There are no cations or anions.
- Calculation:
\[ \text{Valence Electron Count} = \frac{(5 + 2 - 0 + 0)}{2} = \frac{7}{2} = 3.5 \text{ (round down to 3)} \]
- The steric number is 3, which corresponds to sp² hybridization.
- **S-character**:
\[ \text{S-character} = \frac{1}{3} \times 100 \approx 33\% \]

4. **Analyze Diazene (N2H2)**:
- Each nitrogen has 5 valence electrons.
- In diazene, there are 2 hydrogen atoms.
- There are no cations or anions.
- Calculation for each nitrogen:
\[ \text{Valence Electron Count} = \frac{(5 + 2 - 0 + 0)}{2} = \frac{7}{2} = 3.5 \text{ (round down to 3)} \]
- The steric number is 2, which corresponds to sp hybridization.
- **S-character**:
\[ \text{S-character} = \frac{1}{2} \times 100 = 50\% \]

### Conclusion:
Among the NH bonds analyzed:
- NH3 and NH4+ have 25% s-character.
- NH2 has 33% s-character.
- Diazene has 50% s-character.

Thus, the highest amount of s-character is observed in the NH bond of **diazene (N2H2)**.