The molecule having smaller bond angle is

Options

A. `NC_(3)`
B. `AsCI_(3)`
C. `SbCI_(3)`
D. `PCI_(3)`

Answer

C

Explanation

`{:(N),(P),(As),(Sb):}]{:("Group =15"),({:[("Valence"),("electros"):}]=5):}`
`MCI_(3)` has `sp^(2)` hybridized M- electron with one lone pair .Lone pair and bond repulsion decreases bond angle .However, the bond -pair of electron are much father away from the central atom than they are in `NCI_(1)` .Thus lone- pair cause ever greater distrotion in `PCI_(3)AsCI_(3) and SbCI_(2)` ,Tjus bond angle decreases from `NCI_(23)` (maximum ) to `SbCI+_(3)` (minimum)